A BVH tree implement without rotations
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137
server/internal/bvh/bvh.go
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137
server/internal/bvh/bvh.go
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@ -0,0 +1,137 @@
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package bvh
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import (
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"container/heap"
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"math"
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)
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type Vec2 [2]float64
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func (v Vec2) Add(other Vec2) Vec2 { return Vec2{v[0] + other[0], v[1] + other[1]} }
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func (v Vec2) Sub(other Vec2) Vec2 { return Vec2{v[0] - other[0], v[1] - other[1]} }
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func (v Vec2) Max(other Vec2) Vec2 { return Vec2{math.Max(v[0], other[0]), math.Max(v[1], other[1])} }
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func (v Vec2) Min(other Vec2) Vec2 { return Vec2{math.Min(v[0], other[0]), math.Min(v[1], other[1])} }
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type AABB2 struct{ Upper, Lower Vec2 }
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func (aabb AABB2) Union(other AABB2) AABB2 {
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return AABB2{
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Upper: aabb.Upper.Max(other.Upper),
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Lower: aabb.Lower.Min(other.Lower),
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}
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}
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func (aabb AABB2) Surface() float64 {
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d := aabb.Upper.Sub(aabb.Lower)
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return 2 * (d[0] + d[1])
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}
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type Node2 struct {
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box AABB2
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parent *Node2
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children [2]*Node2
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isLeaf bool
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}
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func (n *Node2) findAnotherChild(not *Node2) *Node2 {
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if v := n.children[0]; v != nil && v != not {
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return v
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}
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if v := n.children[1]; v != nil && v != not {
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return v
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}
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return nil
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}
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type Tree2 struct {
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root *Node2
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}
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func (t *Tree2) Insert(leaf AABB2) (n *Node2) {
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n = &Node2{
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box: leaf,
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parent: nil,
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children: [2]*Node2{},
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isLeaf: true,
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}
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if t.root == nil {
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t.root = n
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return
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}
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// Stage 1: find the best sibling for the new leaf
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sibling := t.root
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bestCost := t.root.box.Union(leaf).Surface()
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parentTo := &t.root // the parent's children pointer which point to the sibling
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queue := searchHeap{searchItem{pointer: t.root, parentTo: &t.root}}
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leafCost := leaf.Surface()
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for len(queue) > 0 {
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p := heap.Pop(&queue).(searchItem)
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// determine if node p has the best cost
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mergeSurface := p.pointer.box.Union(leaf).Surface()
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deltaCost := mergeSurface - p.pointer.box.Surface()
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cost := p.inheritedCost + mergeSurface
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if cost < bestCost {
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bestCost = cost
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sibling = p.pointer
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parentTo = p.parentTo
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}
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// determine if it is worthwhile to explore the children of node p.
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inheritedCost := p.inheritedCost + deltaCost // lower bound
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if inheritedCost+leafCost < bestCost {
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if p.pointer.children[0] != nil {
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heap.Push(&queue, searchItem{
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pointer: p.pointer.children[0],
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parentTo: &p.pointer.children[0],
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inheritedCost: inheritedCost,
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})
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}
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if p.pointer.children[1] != nil {
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heap.Push(&queue, searchItem{
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pointer: p.pointer.children[1],
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parentTo: &p.pointer.children[1],
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inheritedCost: inheritedCost,
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})
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}
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}
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}
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// Stage 2: create a new parent
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*parentTo = &Node2{
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box: sibling.box.Union(leaf), // we will calculate in Stage3
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parent: sibling.parent,
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children: [2]*Node2{sibling, n},
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isLeaf: false,
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}
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n.parent = *parentTo
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sibling.parent = *parentTo
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// Stage 3: walk back up the tree refitting AABBs
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for p := *parentTo; p.parent != nil; p = p.parent {
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p.box = p.children[0].box.Union(p.children[1].box)
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//TODO: t.rotate(p)
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}
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return
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}
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type searchHeap []searchItem
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type searchItem struct {
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pointer *Node2
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parentTo **Node2
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inheritedCost float64
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}
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func (h searchHeap) Len() int { return len(h) }
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func (h searchHeap) Less(i, j int) bool {
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return h[i].pointer.box.Surface() < h[j].pointer.box.Surface()
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}
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func (h searchHeap) Swap(i, j int) { h[i], h[j] = h[j], h[i] }
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func (h *searchHeap) Push(x interface{}) { *h = append(*h, x.(searchItem)) }
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func (h *searchHeap) Pop() interface{} {
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old := *h
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n := len(old)
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x := old[n-1]
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*h = old[0 : n-1]
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return x
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}
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